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Exercise 3.2 · Q24

Q.Find the value of: sin⁡(495°)\sin(495°)

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✓ Free question

Step 1: 495°−360°=135°=180°−45°495°-360°=135°=180°-45°.

Step 2: sin⁡135°=sin⁡(180°−45°)=sin⁡45°=22\sin135°=\sin(180°-45°)=\sin45°=\dfrac{\sqrt2}{2} (sine is positive in quadrant II).

✓Final answer

sin⁡495°=22\sin495°=\dfrac{\sqrt2}{2}

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