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Exercise 3.2 · Q28

Q.Find the value of: tan⁡(−690°)\tan(-690°)

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Step 1: tan⁡(−690°)=−tan⁡690°\tan(-690°)=-\tan690° (tangent is an odd function).

Step 2: 690°−360°=330°=360°−30°690°-360°=330°=360°-30°, so tan⁡690°=tan⁡330°=tan⁡(360°−30°)=−tan⁡30°=−13\tan690°=\tan330°=\tan(360°-30°)=-\tan30°=-\dfrac{1}{\sqrt3}. …

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