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Numericals · Q21

Q.Find the value of resistances for the following colour code. 1. Blue Green Red Gold 2. Brown Black Red Silver 3. Red Red Orange Gold 4. Orange White Red Gold 5. Yellow Violet Brown Silver

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Using the colour-code table (section 11.8): each colour maps to a digit (Black=0 ... White=9) and a multiplier (Gold=×10^-1, Silver=×10^-2), with Gold=±5% and Silver=±10% tolerance.

  1. Blue-Green-Red-Gold: digits 6,5; multiplier ×10^2; 65×100=6500 Ω=6.5 kΩ65\times100=6500\,\Omega=6.5\,\text{k}\Omega, tolerance ±5%. Matches the book's printed 6.5 kΩ±5%.

  2. Brown-Black-Red-Silver: digits 1,0; multiplier ×10^2; 10×100=1000 Ω=1.0 kΩ10\times100=1000\,\Omega=1.0\,\text{k}\Omega, tolerance ±10%. Matches the book's printed 1.0 kΩ±10%.

  3. Red-Red-Orange-Gold: digits 2,2; multiplier ×10^3 (Orange); 22×1000=22000 Ω=22 kΩ22\times1000=22000\,\Omega=22\,\text{k}\Omega, tolerance ±5%. The book's own printed answer states 2.2 kΩ±5% -- this is a genuine mismatch against the standard colour-code table (which would need the third band to be Red, ×10^2, to give 2200 Ω=2.2 kΩ, not Orange). We report our own correctly-derived value of 22 kΩ±5% for the colour bands exactly as printed in the question, while flagging that the printed textbook answer of 2.2 kΩ is inconsistent with those stated bands.

  4. Orange-White-Red-Gold: digits 3,9; multiplier ×10^2; 39×100=3900 Ω=3.9 kΩ39\times100=3900\,\Omega=3.9\,\text{k}\Omega, tolerance ±5%. Matches the book's printed 3.9 kΩ±5%. …

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