Q.Find the colour code for the following value of resistor having tolerance ± 10% a) 330Ω b) 100Ω c) 47kΩ d) 160Ω e) 1kΩ

[!TLDR] Writing each value as two significant digits times a power of ten and reading off the matching colours (with Silver for the required ±10% tolerance) gives: a) Orange-Orange-Brown-Silver, b) Brown-Black-Brown-Silver, c) Yellow-Violet-Orange-Silver, d) Brown-Blue-Brown-Silver, e) Brown-Black-Red-Silver. [!ANSWER] a) 330Ω: Orange-Orange-Br …

Each resistance value is first written as (two-digit number)×(power of ten), then each digit and the multiplier are converted to their EIA colours (section 11.8), with the tolerance band fixed at Silver for all five, since ±10% is specified.

a] $330\,\Omega=33\times10^1$: digit 3=Orange, digit 3=Orange, multiplier ×10^1=Brown, tolerance=Silver. Code: Orange-Orange-Brown-Silver.

b] $100\,\Omega=10\times10^1$: digit 1=Brown, digit 0=Black, multiplier ×10^1=Brown, tolerance=Silver. Code: Brown-Black-Brown-Silver.

c] $47\,\text{k}\Omega=47000\,\Omega=47\times10^3$: digit 4=Yellow, digit 7=Violet, multiplier ×10^3=Orange, tolerance=Silver. Code: Yellow-Violet-Orange-Silver.

d] $160\,\Omega=16\times10^1$: digit 1=Brown, digit 6=Blue, multiplier ×10^1=Brown, tolerance=Silver. Code: Brown-Blue-Brown-Silver. …

Express each resistance as two significant digits multiplied by a power of ten, map each digit and the power-of-ten multiplier to its EIA c …

Using a three-digit or single-digit mantissa instead of exactly two significant digits before the multiplier band, which is the …