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MCQ · Q2

Q.An electron is placed between two parallel plates connected to a battery. If the battery is switched on, the electron will (A) be attracted to the +ve plate (B) be attracted to the -ve plate (C) remain stationary (D) will move parallel to the plates

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Once the battery is switched on, a uniform electric field E⃗\vec{E} is set up between the two parallel plates, directed from the positive plate toward the negative plate (the standard convention: field lines point from high to low potential). The force on any charge q placed in this field is F⃗=qE⃗\vec{F}=q\vec{E}. For the electron, q=−eq=-e is negative, so the force F⃗=−eE⃗\vec{F}=-e\vec{E} points in the direction OPPOSITE to E⃗\vec{E} -- that is, from the negative plate TOWARD the positive plate. The electron therefore accelerates toward, and is ultimately attracted to, the positively-charged plate; it moves away from (is repelled by) the negatively-charged plate. This is the same basic principle by which electron beams are steered inside older cathode-ray-tube devices, and by which ions are separated by charge sign in a mass spectrometer. [!ANSWER] (A) be attracted to the +ve plate.

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