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Numericals · Q22

Q.Three equal charges of 10×10−810\times10^{-8} C each, located at the corners of a right triangle whose sides are 15 cm, 20 cm and 25 cm respectively. Find the force exerted on the charge located at the 90∘90^\circ angle.

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Since 152+202=225+400=625=25215^2+20^2=225+400=625=25^2, the right angle of the triangle is between the 15 cm and 20 cm sides, with 25 cm as the hypotenuse. Each charge is q=10×10−8=1×10−7q=10\times10^{-8}=1\times10^{-7} C. …

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