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Q.Explain graphical method to determine activation energy of a reaction.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2016Subjective· 2mImportance★★★★★
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Plotting log⁡k\log k vs 1/T1/T gives a straight line of slope −Ea/2.303R-E_a/2.303R, from which EaE_a is calculated.

The Arrhenius equation relates the rate constant kk of a reaction to temperature: k=A e−Ea/RTk = A\,e^{-E_a/RT}, where AA is the pre-exponential (frequency) factor and EaE_a is the activation energy.

Taking logarithm (base 10) of both sides: log⁡k=log⁡A−Ea2.303 R T\log k = \log A - \dfrac{E_a}{2.303\,R\,T}

This is of the form y=c+mxy = c + mx, where y=log⁡ky = \log k, x=1/Tx = 1/T, intercept c=log⁡Ac = \log A, and slope m=−Ea2.303Rm = -\dfrac{E_a}{2.303R}.

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