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Q.ix. What fraction of molecules in a gas at 300 K collide with an energy equal to activation energy of 50 kJ/mol ? (2 ×\times 10−9^{-9})

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Step 1. Ea=50000E_a=50000 J/mol, T=300T=300 K, R=8.314R=8.314 J/K/mol.

Step 2. f=e−Ea/RT=e−50000/(8.314×300)=e−50000/2494.2=e−20.05f=e^{-E_a/RT}=e^{-50000/(8.314\times300)}=e^{-50000/2494.2}=e^{-20.05}. …

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