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Chemistry · Ch 3 — Ionic Equilibria

Buffer action

3.8.2

Buffer action

Let us consider sodium acetate - acetic acid buffer. Here sodium acetate is a strong electrolyte which dissociates completely in water producing large concentration of CH3COO−\mathrm{CH_3COO^{-}} as follows :

CH3COONa(aq)→CH3COO−(aq)+Na+(aq)\mathrm{CH_3COONa(aq)} \rightarrow \mathrm{CH_3COO^{-}(aq)} + \mathrm{Na^{+}(aq)}

On the other hand since the acetic acid is a weak acid, the concentration of undissociated CH3COOH\mathrm{CH_3COOH} molecules is usually high. If a strong acid is added to this solution the added H+\mathrm{H^{+}} ions will be consumed by the conjugate base CH3COO−\mathrm{CH_3COO^{-}} present in large concentration. Similarly, if small amount of base is added, the added OH−\mathrm{OH^{-}} ions will be neutralized by the large concentration of acetic acid as shown in the following reactions :

CH3COO−(aq)(large concentration)+H+(aq)(added acid)→CH3COOH(aq)\underset{\text{(large concentration)}}{\mathrm{CH_3COO^{-}(aq)}} + \underset{\text{(added acid)}}{\mathrm{H^{+}(aq)}} \rightarrow \mathrm{CH_3COOH(aq)}

CH3COOH(aq)(large concentration)+OH−(aq)(added base)→CH3COO−(aq)+H2O(l)\underset{\text{(large concentration)}}{\mathrm{CH_3COOH(aq)}} + \underset{\text{(added base)}}{\mathrm{OH^{-}(aq)}} \rightarrow \mathrm{CH_3COO^{-}(aq)} + \mathrm{H_2O}(l) …