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Chemistry · Ch 3 — Ionic Equilibria

Common ion effect and solubility

3.10.1

Common ion effect and solubility

The presence of a common ion also affects the solubility of a sparingly soluble salt. Consider, the solubility equilibrium of AgCl,

AgCl(s)⇌Ag+(aq)+Cl−(aq)\mathrm{AgCl(s)} \rightleftharpoons \mathrm{Ag^{+}(aq)} + \mathrm{Cl^{-}(aq)}

The solubility product of AgCl is

Ksp=[Ag+][Cl−]K_{sp} = [\mathrm{Ag^{+}}][\mathrm{Cl^{-}}]

Suppose AgNO3\mathrm{AgNO_3} is added to the saturated solution of AgCl. The salt AgNO3\mathrm{AgNO_3} being a strong electrolyte dissociates completely in the solution.

AgNO3(aq)→Ag+(aq)+NO3−(aq)\mathrm{AgNO_3(aq)} \rightarrow \mathrm{Ag^{+}(aq)} + \mathrm{NO_3^{-}(aq)}

The dissociation of AgCl and AgNO3\mathrm{AgNO_3} produce a common Ag+\mathrm{Ag^{+}} ion. The concentration of Ag+\mathrm{Ag^{+}} ion in the solution increases owing to complete dissociation of AgNO3\mathrm{AgNO_3}. According to Le-Chatelier's principle the addition of Ag+\mathrm{Ag^{+}} ions from AgNO3\mathrm{AgNO_3} to the solution of AgCl shifts the solubility equilibrium of AgCl from right to left. The reverse reaction in which AgCl precipitates, is favoured until the solubility equilibrium is re-established. The value of KspK_{sp}, however, remains the same since it is an equilibrium constant. The solubility of a sparingly soluble compound, thus decreases with the presence of a common ion in solution.

Note

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