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Questions 4-14 · Q9

Q.An element with molar mass 27 g/mol forms cubic unit cell with edge length of 405 pm. If density of the element is 2.7 g/cm³. What is the nature of cubic unit cell? (fcc or ccp)

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Step 1. Convert the edge length: a=405 pm=4.05×10−8 cma=405\text{ pm}=4.05\times10^{-8}\text{ cm}, so a3=6.643×10−23 cm3a^3=6.643\times10^{-23}\text{ cm}^3.

Step 2. Rearranging ρ=nMa3NA\rho=\dfrac{nM}{a^3N_A} for nn: n=ρa3NAM=2.7×6.643×10−23×6.022×102327n=\dfrac{\rho a^3N_A}{M}=\dfrac{2.7\times6.643\times10^{-23}\times6.022\times10^{23}}{27}.

Step 3. Evaluating: 2.7×6.643×6.022≈108.02.7\times6.643\times6.022\approx108.0, so n=108.0/27=4.0n=108.0/27=4.0. …

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