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Chemistry · Ch 1 — Solid State

Relationship between molar mass, density of the substance and unit cell edge length

1.5.2

Relationship between molar mass, density of the substance and unit cell edge length

The relationship between the density of a substance, its molar mass and its unit cell edge length is deduced in the following steps. If the edge length of the cubic unit cell is aa, the volume of the unit cell is a3a^3. If the mass of one particle is mm and the unit cell contains nn particles, then

mass of unit cell=m×n...(1.1)\text{mass of unit cell} = m \times n \qquad \text{...(1.1)}

The density of the unit cell is the same as the density ρ\rho of the substance:

ρ=mass of unit cellvolume of unit cell=m na3...(1.2)\rho = \frac{\text{mass of unit cell}}{\text{volume of unit cell}} = \frac{m\,n}{a^3} \qquad \text{...(1.2)}

The molar mass MM of the substance is the mass of one particle multiplied by the number of particles per mole (Avogadro's number NAN_A), that is M=m NAM = m\,N_A, which rearranges to

m=MNA...(1.3)m = \frac{M}{N_A} \qquad \text{...(1.3)}

Substituting Eq. (1.3) into Eq. (1.2) gives the working relation used throughout this chapter:

ρ=n Ma3 NA...(1.4)\rho = \frac{n\,M}{a^3\,N_A} \qquad \text{...(1.4)} …