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Miscellaneous Exercise 4 · Q64

Q.Evaluate: ∫0π/4tan⁡3x1+cos⁡2x dx\int_0^{\pi/4} \dfrac{\tan^3 x}{1+\cos 2x}\,dx

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tan⁡3x1+cos⁡2x=tan⁡3x2cos⁡2x=tan⁡3xsec⁡2x2\dfrac{\tan^3x}{1+\cos2x}=\dfrac{\tan^3x}{2\cos^2x}=\dfrac{\tan^3x\sec^2x}2. Let t=tan⁡x, dt=sec⁡2x dxt=\tan x,\ dt=\sec^2x\,dx; limits x=0→t=0x=0\to t=0, x=π/4→t=1x=\pi/4\to t=1. …

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