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Miscellaneous Exercise 4 · Q65

Q.Evaluate: ∫01t51−t2 dt\int_0^1 t^5\sqrt{1-t^2}\,dt

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Let u=t2, du=2t dtu=t^2,\ du=2t\,dt, so t5 dt=t4⋅t dt=u2⋅du2t^5\,dt=t^4\cdot t\,dt=u^2\cdot\tfrac{du}2.

∫01t51−t2 dt=12∫01u2(1−u)1/2 du=12 B(3,32)=12⋅Γ(3)Γ(3/2)Γ(9/2).\int_0^1t^5\sqrt{1-t^2}\,dt=\frac12\int_0^1u^2(1-u)^{1/2}\,du=\frac12\,B(3,\tfrac32)=\frac12\cdot\frac{\Gamma(3)\Gamma(3/2)}{\Gamma(9/2)}. …

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