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Miscellaneous Exercise 4 · Q81

Q.If ∫0ax dx=2a∫0π/2sin⁡3x dx\int_0^a \sqrt{x}\,dx = 2a\displaystyle\int_0^{\pi/2}\sin^3x\,dx, then find the value of ∫aa+1x dx\int_a^{a+1} x\,dx

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LHS of the given equation: ∫0ax dx=23a3/2\int_0^a\sqrt x\,dx=\dfrac23a^{3/2}. RHS: 2a∫0π/2sin⁡3x dx=2a⋅23=4a32a\int_0^{\pi/2}\sin^3x\,dx=2a\cdot\dfrac23=\dfrac{4a}3 (using the reduction formula for odd n=3n=3: n−1n=23\frac{n-1}n=\frac23, Section 4.2.3).

23a3/2=4a3 ⟹ a3/2=2a ⟹ a1/2=2 ⟹ a=4(a≠0).\frac23a^{3/2}=\frac{4a}3\ \Longrightarrow\ a^{3/2}=2a\ \Longrightarrow\ a^{1/2}=2\ \Longrightarrow\ a=4\quad(a\ne0). …

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