Skip to content
Exercise 6.4 · Q67

Q.Solve: (x2+3xy+y2)dx−x2 dy=0(x^2+3xy+y^2)dx-x^2\,dy=0

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
38% · 67/177 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

(x2+3xy+y2)dx−x2dy=0(x^2+3xy+y^2)dx-x^2dy=0 gives dydx=1+3v+v2\dfrac{dy}{dx}=1+3v+v^2 under y=vxy=vx: v+xdvdx=1+3v+v2v+x\dfrac{dv}{dx}=1+3v+v^2, so xdvdx=1+2v+v2=(v+1)2x\dfrac{dv}{dx}=1+2v+v^2=(v+1)^2, i.e. dv(v+1)2=dxx\dfrac{dv}{(v+1)^2}=\dfrac{dx}{x}. Integrating: −1v+1=log⁡x+c-\dfrac{1}{v+1}=\log x+c. Substituting …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.