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Exercise 7.1 · Q9

Q.Solve graphically : 2x−3≥02x - 3 \ge 0

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Rewrite 2x−3≥02x - 3 \ge 0 as 2x≥32x \ge 3, i.e. x≥32=1.5x \ge \tfrac32 = 1.5. The boundary is the vertical line x=1.5x = 1.5, drawn solid. Any point to its right (e.g. (3,0)(3,0)) gives 2(3)−3=3≥02(3)-3=3\ge0, true, confirming the right side is the solution. …

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