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Question 118 of 139

Q.The joint equation of the pair of lines passing through (2,3)(2, 3) and parallel to the coordinate axes is

(a) xy−3x−2y+6=0xy - 3x - 2y + 6 = 0
(b) xy+3x+2y+6=0xy + 3x + 2y + 6 = 0
(c) xy=0xy = 0
(d) xy−3x−2y−6=0xy - 3x - 2y - 6 = 0
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2016MCQ· 2mImportance★★★★★
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Lines through (2,3)(2,3) parallel to the axes are x=2x=2 and y=3y=3; their joint equation is the product of these two factors.

A line through (2,3)(2,3) parallel to the X-axis is y=3y=3, i.e. y−3=0y-3=0.

A line through (2,3)(2,3) parallel to the Y-axis is x=2x=2, i.e. x−2=0x-2=0.

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