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Exercise 7.2 · Q25

Q.Verify which of the following is p.d.f. of r.v. X :

(ii) f
(x) = x, for 0 ≤ x ≤ 1 and = 2 – x for 1 < x < 2
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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✓ Free question

On [0,1][0,1], f(x)=x≥0f(x)=x\ge0; on (1,2)(1,2), f(x)=2−xf(x)=2-x, positive since x<2x<2. Total area: ∫01x dx+∫12(2−x) dx=12+0.5=1\int_0^1 x\,dx + \int_1^2 (2-x)\,dx = \dfrac12 + 0.5=1. Both p.d.f. conditions hold.

✓Final answer

This piecewise f is a valid p.d.f. (a triangular density on [0,2]).

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