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Exercise 7.2 · Q26

Q.Verify which of the following is p.d.f. of r.v. X :

(iii) f
(x) = 2, for 0 ≤ x ≤ 1
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✓ Free question

f(x)=2≥0f(x)=2\ge0 on [0,1][0,1], so non-negativity holds. But ∫012 dx=2≠1\int_0^1 2\,dx = 2\ne1, so the area under the curve is not 1, and the second p.d.f. condition fails.

✓Final answer

f(x) = 2 on [0,1] is NOT a valid p.d.f., since its total area is 2, not 1.

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