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Exercise 3.1 · Q6

Q.Find the principal solutions of the following equation: tan⁡θ=−1\tan\theta = -1

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tan⁡θ=−1\tan\theta=-1 is negative, so θ\theta is in the second or fourth quadrant, reference angle π4\dfrac{\pi}{4} (since tan⁡π4=1\tan\dfrac{\pi}{4}=1). Second quadrant: θ=π−π4=3π4\theta=\pi-\dfrac{\pi}{4}=\dfrac{3\pi}{4}. Fourth quadrant: $\t …

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