Mathematics · Class 12 Science
Ch 3Trigonometric Functions — Class 12 Mathematics, concept-first.
We are already familiar with algebraic equations such as , which are satisfied by only finitely many values of . In this chapter we turn instead to trigonometric equations -- equations involving one or more trigonometric functions of an unknown angle.
Key concepts
Hover a concept to preview it and jump to its most relevant Q&A.
Trigonometric Equations and Principal Solutions
A trigonometric equation is any equation involving one or more trigonometric functions of an unknown angle, such as or .
Most relevant Q&A
- Find the principal solutions of the following equation: $\cos\theta = \frac{1}{2}$Free
- Find the principal solutions of the following equation: $\sec\theta = \frac{2}{\sqrt{3}}$Free
- Find the principal solutions of the following equation: $\cot\theta = \sqrt{3}$Free
- Find the principal solutions of the following equation: $\cot\theta = 0$Preview
- Find the principal solutions of the following equation: $\sin\theta = -\frac{1}{2}$Preview
In previous exams
How often this chapter’s concepts have been examined — real appearance data, never estimated.
Chapter contents
The NCERT structure, section by section. Open a section to see its questions, then read the concept-first solution.
Introduction
We are already familiar with algebraic equations such as , which are satisfied by only finitely many values of .
Trigonometric Equations and their Solutions
An algebraic equation like is satisfied by only finitely many values of . A trigonometric equation is an equation that involves one or more trigonometric functions of an unknown angle, for example , ,…
+−Exercise 3.1i24 questions
- Q1Find the principal solutions of the following equation: $\cos\theta = \frac{1}{2}$Free
- Q2Find the principal solutions of the following equation: $\sec\theta = \frac{2}{\sqrt{3}}$Free
- Q3Find the principal solutions of the following equation: $\cot\theta = \sqrt{3}$Free
- Q4Find the principal solutions of the following equation: $\cot\theta = 0$Preview
- Q5Find the principal solutions of the following equation: $\sin\theta = -\frac{1}{2}$Preview
- Q6Find the principal solutions of the following equation: $\tan\theta = -1$Preview
- Q7Find the principal solutions of the following equation: $\sqrt{3}\,\text{cosec}\,\theta + 2 = 0$Preview
- Q8Find the general solution of the following equation: $\sin\theta = \frac{1}{2}$Preview
- Q9Find the general solution of the following equation: $\cos\theta = \frac{\sqrt{3}}{2}$Preview
- Q10Find the general solution of the following equation: $\tan\theta = \frac{1}{\sqrt{3}}$Preview
- Q11Find the general solution of the following equation: $\cot\theta = 0$Preview
- Q12Find the general solution of the following equation: $\sec\theta = \sqrt{2}$Preview
- Q13Find the general solution of the following equation: $\text{cosec}\,\theta = -2$Preview
- Q14Find the general solution of the following equation: $\tan\theta = -1$Preview
- Q15Find the general solution of the following equation: $\sin 2\theta = \frac{1}{2}$Preview
- Q16Find the general solution of the following equation: $\tan\dfrac{2\theta}{3} = \sqrt{3}$Preview
- Q17Find the general solution of the following equation: $\cot 4\theta = -1$Preview
- Q18Find the general solution of the following equation: $4\cos^2\theta = 3$Preview
- Q19Find the general solution of the following equation: $4\sin^2\theta = 1$Preview
- Q20Find the general solution of the following equation: $\cos 4\theta = \cos 2\theta$Preview
- Q21Find the general solution of the following equation: $\sin\theta = \tan\theta$Preview
- Q22Find the general solution of the following equation: $\tan 3\theta = 3\tan\theta$Preview
- Q23Find the general solution of the following equation: $\cos\theta + \sin\theta = 1$Preview
- Q24Which of the following equations have solutions? (i) $\cos 2\theta = -1$ (ii) $\cos^2\theta = -1$ (iii) $2\sin\theta = 3$ (iv) $3\tan\theta…Preview
Trigonometric Equations and Principal Solutions
A solution of a trigonometric equation is any value of the angle that makes the equation true when substituted in. For example, satisfies because ; so does , because as well.
The General Solution
Since a trigonometric equation has infinitely many solutions repeating every period, we want one formula — parametrised by an integer — that generates every solution. This is the general solution.
Solution of Triangle
Having solved trigonometric equations, we now turn to a second classical application of trigonometry: relating the angles and sides of a triangle to each other so precisely that knowing any three elem…
+−Exercise 3.2i23 questions
- Q25Find the Cartesian co-ordinates of the point whose polar co-ordinates are $\left(2, \dfrac{\pi}{4}\right)$Free
- Q26Find the Cartesian co-ordinates of the point whose polar co-ordinates are $\left(4, \dfrac{\pi}{2}\right)$Free
- Q27Find the Cartesian co-ordinates of the point whose polar co-ordinates are $\left(\dfrac{3}{4}, \dfrac{3\pi}{4}\right)$Free
- Q28Find the Cartesian co-ordinates of the point whose polar co-ordinates are $\left(\dfrac{1}{2}, \dfrac{7\pi}{3}\right)$Preview
- Q29Find the polar co-ordinates of the point whose Cartesian co-ordinates are $\left(\sqrt{2}, \sqrt{2}\right)$Preview
- Q30Find the polar co-ordinates of the point whose Cartesian co-ordinates are $\left(0, \dfrac{1}{2}\right)$Preview
- Q31Find the polar co-ordinates of the point whose Cartesian co-ordinates are $\left(1, -\sqrt{3}\right)$Preview
- Q32Find the polar co-ordinates of the point whose Cartesian co-ordinates are $\left(\dfrac{3}{2}, \dfrac{3\sqrt{3}}{2}\right)$Preview
- Q33In $\triangle ABC$, if $A = 45^\circ$, $B = 60^\circ$ then find the ratio of its sides.Preview
- Q34In $\triangle ABC$, prove that $\sin\left(\dfrac{B-C}{2}\right) = \dfrac{b-c}{a}\cos\dfrac{A}{2}$.Preview
- Q35With usual notations prove that $2\left[a\sin^2\dfrac{C}{2} + c\sin^2\dfrac{A}{2}\right] = a - b + c$.Preview
- Q36In $\triangle ABC$, prove that $a^3\sin(B-C) + b^3\sin(C-A) + c^3\sin(A-B) = 0$.Preview
- Q37In $\triangle ABC$, if $\cot A$, $\cot B$, $\cot C$ are in A.P. then show that $a^2$, $b^2$, $c^2$ are also in A.P.Preview
- Q38In $\triangle ABC$, if $a\cos A = b\cos B$ then prove that the triangle is right angled or an isosceles triangle.Preview
- Q39With usual notations prove that $2(bc\cos A + ac\cos B + ab\cos C) = a^2 + b^2 + c^2$.Preview
- Q40In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $\cos A$.Preview
- Q41In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $\sin\dfrac{A}{2}$.Preview
- Q42In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $\cos\dfrac{A}{2}$.Preview
- Q43In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $\tan\dfrac{A}{2}$.Preview
- Q44In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $A(\triangle ABC)$.Preview
- Q45In $\triangle ABC$, if $a = 18$, $b = 24$, $c = 30$ then find the value of $\sin A$.Preview
- Q46In $\triangle ABC$, prove that $(b+c-a)\tan\dfrac{A}{2} = (c+a-b)\tan\dfrac{B}{2} = (a+b-c)\tan\dfrac{C}{2}$.Preview
- Q47In $\triangle ABC$, prove that $\sin\dfrac{A}{2}\sin\dfrac{B}{2}\sin\dfrac{C}{2} = \dfrac{[A(\triangle ABC)]^2}{abcs}$.Preview
Polar Co-ordinates
Fix a point in a plane, called the pole, and a fixed ray starting at , called the polar axis. For any point in the plane other than , let (the length of the segment joining and ) and let (the angle th…
Relation between the Cartesian and the Polar Co-ordinates
To connect polar co-ordinates to the familiar Cartesian system, take the polar axis as the X-axis and the line through perpendicular to as the Y-axis, with the pole as the origin.
Solving a Triangle
The three sides and three angles of a triangle are together called its elements. Given any three of the six elements, provided at least one of them is a side, the remaining three elements can be found…
The Sine Rule
The Sine Rule. In , where is the circumradius (the radius of the circle passing through , , ).
The Cosine Rule
The Cosine Rule. In : (i) ; (ii) ; (iii) .
The Projection Rule
The Projection Rule. In : (i) ; (ii) ; (iii) .
Applications of the Sine Rule, the Cosine Rule and the Projection Rule
This section develops three important toolkits built from the Sine, Cosine, and Projection Rules. Throughout, (so is the semi-perimeter).
Inverse Trigonometric Functions
So far we have treated , , , etc. as functions that take an angle and produce a number. This section asks the reverse question: given the number, can we recover the angle? Recall that a function has a…
+−Exercise 3.3i18 questions
- Q48Find the principal value of $\sin^{-1}\dfrac{1}{2}$Free
- Q49Find the principal value of $\text{cosec}^{-1}(2)$Free
- Q50Find the principal value of $\tan^{-1}(-1)$Free
- Q51Find the principal value of $\tan^{-1}(-\sqrt{3})$Preview
- Q52Find the principal value of $\sin^{-1}\left(-\dfrac{1}{2}\right)$Preview
- Q53Find the principal value of $\cos^{-1}\left(-\dfrac{1}{2}\right)$Preview
- Q54Evaluate: $\tan^{-1}(1) + \cos^{-1}\dfrac{1}{2} + \sin^{-1}\dfrac{1}{2}$Preview
- Q55Evaluate: $\cos^{-1}\dfrac{1}{2} + 2\sin^{-1}\dfrac{1}{2}$Preview
- Q56Evaluate: $\tan^{-1}\sqrt{3} - \sec^{-1}(-2)$Preview
- Q57Evaluate: $\text{cosec}^{-1}(-\sqrt{2}) + \cot^{-1}(\sqrt{3})$Preview
- Q58Prove the following: $\sin^{-1}\dfrac{1}{\sqrt{2}} - 3\sin^{-1}\dfrac{\sqrt{3}}{2} = -\dfrac{3\pi}{4}$Preview
- Q59Prove the following: $\sin^{-1}\left(-\dfrac{1}{2}\right) + \cos^{-1}\left(-\dfrac{\sqrt{3}}{2}\right) = \cos^{-1}\left(-\dfrac{1}{2}\right)…Preview
- Q60Prove the following: $\sin^{-1}\dfrac{3}{5} + \cos^{-1}\dfrac{12}{13} = \sin^{-1}\dfrac{56}{65}$Preview
- Q61Prove the following: $\cos^{-1}\dfrac{3}{5} + \cos^{-1}\dfrac{4}{5} = \dfrac{\pi}{2}$Preview
- Q62Prove the following: $\tan^{-1}\dfrac{1}{2} + \tan^{-1}\dfrac{1}{3} = \dfrac{\pi}{4}$Preview
- Q63Prove the following: $2\tan^{-1}\dfrac{1}{3} = \tan^{-1}\dfrac{3}{4}$Preview
- Q64Prove the following: $\tan^{-1}\left(\dfrac{\cos\theta + \sin\theta}{\cos\theta - \sin\theta}\right) = \dfrac{\pi}{4} + \theta$, if $\theta…Preview
- Q65Prove the following: $\tan^{-1}\sqrt{\dfrac{1-\cos\theta}{1+\cos\theta}} = \dfrac{\theta}{2}$, if $\theta \in (0, \pi)$Preview
Inverse Sine Function
Consider restricted to . Graphically this restriction is one-one (strictly increasing) and onto , so its inverse exists, called the inverse sine function and denoted .
Inverse Cosine Function
Consider restricted to . Graphically this restriction is one-one (strictly decreasing) and onto , so its inverse exists, called the inverse cosine function, denoted .
Inverse Tangent Function
Consider restricted to . Graphically this restriction is one-one and onto , so its inverse exists, called the inverse tangent function, denoted . For and , we write if .
Inverse Cosecant Function
Consider restricted to . Graphically this restriction is one-one and onto , so its inverse exists, called the inverse cosecant function, denoted . For and , we write if .
Inverse Secant Function
Consider restricted to . Graphically this restriction is one-one and onto , so its inverse exists, called the inverse secant function, denoted . For and , we write if .
Inverse Cotangent Function
Consider restricted to . Graphically this restriction is one-one and onto , so its inverse exists, called the inverse cotangent function, denoted . For and , we write if .
Principal Values of Inverse Trigonometric Functions
This short section gathers the domain and principal-value range of all six inverse trigonometric functions in one place, now that each has been defined individually in the six preceding sub-sections:…
Properties of Inverse Trigonometric Functions
Properties of Inverse Trigonometric Functions.
Sample & Board Papers
Sample papers and previous-year board questions for this subject.
+−Show 39 questionsHide questions39 questions
- Q1If $\sin^{-1}(1-x) - 2\sin^{-1}x = \dfrac{\pi}{2}$ then $x$ is (a) $-\dfrac{1}{2}$ (b) $1$ (c) $0$ (d) $\dfrac{1}{2}$Preview
- Q2In $\triangle ABC$ with the usual notations prove that $(a - b)^2 \cos^2\left(\dfrac{C}{2}\right) + (a + b)^2 \sin^2\left(\dfrac{C}{2}\right…Preview
- Q3Find the general solution of $\sin x + \sin 3x + \sin 5x = 0$.Preview
- Q4In $\triangle ABC$, if $a = 13$, $b = 14$ and $c = 15$, then $\sin\left(\dfrac{A}{2}\right) =$ (a) $\dfrac{1}{5}$ (b) $\sqrt{\dfrac{1}{5}}$…Preview
- Q5In $\triangle ABC$, prove that $a(b\cos C - c\cos B) = b^2 - c^2$.Preview
- Q6Find the general solution of the equation $\sin 2x + \sin 4x + \sin 6x = 0$Preview
- Q7Show that $\cos^{-1}\left(\dfrac{4}{5}\right) + \cos^{-1}\left(\dfrac{12}{13}\right) = \cos^{-1}\left(\dfrac{33}{65}\right)$Preview
- Q8The principal solutions of $\sec x = \dfrac{2}{\sqrt{3}}$ are ______. (a) $\dfrac{\pi}{3}, \dfrac{11\pi}{6}$ (b) $\dfrac{\pi}{6}, \dfrac{11\…Preview
- Q9In $\triangle ABC$, prove that $\tan\left(\dfrac{C-A}{2}\right) = \left(\dfrac{c-a}{c+a}\right)\cot\dfrac{B}{2}$.Preview
- Q10Prove that: $\sin^{-1}\left(\dfrac{3}{5}\right) + \cos^{-1}\left(\dfrac{12}{13}\right) = \sin^{-1}\left(\dfrac{56}{65}\right)$.Preview
- Q11The principal solutions of $\cot x = -\sqrt{3}$ are ________. (a) $\dfrac{\pi}{6}, \dfrac{5\pi}{6}$ (b) $\dfrac{5\pi}{6}, \dfrac{7\pi}{6}$ (…Preview
- Q12In $\triangle ABC$, prove that $\sin\left(\dfrac{B-C}{2}\right) = \left(\dfrac{b-c}{a}\right)\cos\left(\dfrac{A}{2}\right)$ **OR** Show that…Preview
- Q13In $\triangle ABC$, with usual notations prove that $b^2 = c^2 + a^2 - 2ca\cos B$ **OR** In $\triangle ABC$, with usual notations prove that…Preview
- Q14In $\triangle ABC$, if $a = 2$, $b = 3$ and $\sin A = \dfrac{2}{3}$, then $\angle B = $ ________. (a) $\dfrac{\pi}{4}$ (b) $\dfrac{\pi}{2}$…Preview
- Q15Find the general solution of $\tan 2x = 0$Preview
- Q16Show that: $\sin^{-1}\left(\dfrac{8}{17}\right) + \sin^{-1}\left(\dfrac{3}{5}\right) = \sin^{-1}\left(\dfrac{77}{85}\right)$.Preview
- Q17In $\triangle ABC$, if $a+b+c=2s$, then prove that $\sin\left(\dfrac{A}{2}\right)=\sqrt{\dfrac{(s-b)(s-c)}{bc}}$, with usual notations.Preview
- Q18In $\triangle ABC$ if $c^2+a^2-b^2=ac$, then $\angle B = $ ________. (a) $\dfrac{\pi}{4}$ (b) $\dfrac{\pi}{3}$ (c) $\dfrac{\pi}{2}$ (d) $\df…Preview
- Q19Find the principal value of $\cot^{-1}\left(\dfrac{-1}{\sqrt 3}\right)$.Preview
- Q20Find the principal solutions of $\cot \theta = 0$Preview
- Q21Find the cartesian co-ordinates of the point whose polar co-ordinates are $\left(\dfrac{1}{2}, \dfrac{\pi}{3}\right)$.Preview
- Q22If $2\tan^{-1}(\cos x) = \tan^{-1}(2\csc x)$, then find the value of $x$.Preview
- Q23In $\triangle ABC$, if $c^2+a^2-b^2=ac$, then $\angle B = $ ________. (a) $\dfrac{\pi}{4}$ (b) $\dfrac{\pi}{3}$ (c) $\dfrac{\pi}{2}$ (d) $\d…Preview
- Q24Find the cartesian co-ordinates of the point whose polar co-ordinates are $\left(\sqrt 2, \dfrac{\pi}{4}\right)$.Preview
- Q25Find the general solution of $\sin\theta + \sin 3\theta + \sin 5\theta = 0$Preview
- Q26If $-1 \le x \le 1$, then prove that $\sin^{-1}x + \cos^{-1}x = \dfrac{\pi}{2}$Preview
- Q27The principle solutions of the equation $\cos\theta = \dfrac{1}{2}$ are ____. (a) $\dfrac{\pi}{6}, \dfrac{5\pi}{6}$ (b) $\dfrac{\pi}{3}, \df…Preview
- Q28In $\triangle ABC$, if $a=18, b=24$ and $c=30$ then find the value of $\sin\left(\dfrac{A}{2}\right)$.Preview
- Q29Prove that: $\tan^{-1}\left(\dfrac{1}{2}\right)+\tan^{-1}\left(\dfrac{1}{3}\right)=\dfrac{\pi}{4}$Preview
- Q30In $\triangle ABC$, prove that: $\dfrac{\cos A}{a}+\dfrac{\cos B}{b}+\dfrac{\cos C}{c}=\dfrac{a^2+b^2+c^2}{2abc}$.Preview
- Q31In $\triangle ABC$, $(a+b)\cdot\cos C+(b+c)\cos A+(c+a)\cdot\cos B$ is equal to ____. (a) $a-b+c$ (b) $a+b-c$ (c) $a+b+c$ (d) $a-b-c$Preview
- Q32Find the general solution of $\tan^2\theta=1$.Preview
- Q33Prove that: $2\tan^{-1}\left(\dfrac13\right)+\cos^{-1}\left(\dfrac35\right)=\dfrac{\pi}{2}$.Preview
- Q34In $\triangle ABC$ if $a=13$, $b=14$, $c=15$ then find the values of (i) $\sec A$ (ii) $\csc \dfrac{A}{2}$.Preview
- Q35If $\tan^{-1}(2x)+\tan^{-1}(3x)=\dfrac{\pi}{4}$, then $x=$ ____. (a) -1 (b) $\dfrac16$ (c) $\dfrac13$ (d) $\dfrac32$Preview
- Q36Evaluate: $\cos^{-1}\left(\dfrac12\right)+2\sin^{-1}\left(\dfrac12\right)$Preview
- Q37In $\triangle ABC$, prove that $a(b\cos C - c\cos B)=b^2-c^2$.Preview
- Q38Find the general solution of $4\cos^2\theta=3$.Preview
- Q39In $\triangle ABC$, if $A=45°$, $B=60°$ then find the ratio of its sides.Preview
More questions
+−Show 73 questionsHide questions73 questions
- Q66The principal solutions of equation $\sin\theta = -\dfrac{1}{2}$ are ____________. (a) $\dfrac{\pi}{6}, \dfrac{5\pi}{6}$ (b) $\dfrac{7\pi}{6…Free
- Q67The principal solutions of equation $\cot\theta = \sqrt{3}$ are ____________. (a) $\dfrac{\pi}{6}, \dfrac{7\pi}{6}$ (b) $\dfrac{\pi}{6}, \df…Free
- Q68The general solution of $\sec x = \sqrt{2}$ is __________. (a) $2n\pi \pm \dfrac{\pi}{4}$, $n \in Z$ (b) $2n\pi \pm \dfrac{\pi}{2}$, $n \in…Free
- Q69If $\cos p\theta = \cos q\theta$, $p \ne q$ then ________. (a) $\theta = \dfrac{2n\pi}{p \pm q}$ (b) $\theta = 2n\pi$ (c) $\theta = 2n\pi +…Preview
- Q70If polar co-ordinates of a point are $\left(2, \dfrac{\pi}{4}\right)$ then its Cartesian co-ordinates are ______. (a) $(2, \sqrt{2})$ (b) $(…Preview
- Q71If $\sqrt{3}\cos x - \sin x = 1$, then the general value of $x$ is _________. (a) $2n\pi \pm \dfrac{\pi}{3}$ (b) $2n\pi \pm \dfrac{\pi}{6}$…Preview
- Q72In $\triangle ABC$ if $\angle A = 45^\circ$, $\angle B = 30^\circ$ then $a:b:c =$ _________. (a) $2 : \sqrt{2} : \sqrt{3}+1$ (b) $\sqrt{2} :…Preview
- Q73In $\triangle ABC$, if $c^2 + a^2 - b^2 = ac$, then $\angle B =$ __________. (a) $\dfrac{\pi}{4}$ (b) $\dfrac{\pi}{3}$ (c) $\dfrac{\pi}{2}$…Preview
- Q74In $\triangle ABC$, $ac\cos B - bc\cos A =$ ____________. (a) $a^2-b^2$ (b) $b^2-c^2$ (c) $c^2-a^2$ (d) $a^2-b^2-c^2$Preview
- Q75If in a triangle, the angles are in A.P. and $b : c = \sqrt{3} : \sqrt{2}$ then $A$ is equal to __________. (a) $30^\circ$ (b) $60^\circ$ (c…Preview
- Q76$\cos^{-1}\left(\cos\dfrac{7\pi}{6}\right) =$ ___________. (a) $\dfrac{7\pi}{6}$ (b) $\dfrac{5\pi}{6}$ (c) $\dfrac{\pi}{6}$ (d) $\dfrac{3\pi…Preview
- Q77The principal value of $\sin^{-1}\left(-\dfrac{\sqrt{3}}{2}\right)$ is ____________. (a) $-\dfrac{2\pi}{3}$ (b) $\dfrac{4\pi}{3}$ (c) $\dfra…Preview
- Q78If $\sin^{-1}\dfrac{4}{5} + \cos^{-1}\dfrac{12}{13} = \sin^{-1}a$, then $a =$ _____________. (a) $\dfrac{63}{65}$ (b) $\dfrac{62}{65}$ (c) $…Preview
- Q79If $\tan^{-1}(2x) + \tan^{-1}(3x) = \dfrac{\pi}{4}$, then $x =$ (a) $-1$ (b) $\dfrac{1}{6}$ (c) $\dfrac{2}{6}$ (d) $\dfrac{3}{2}$Preview
- Q80$2\tan^{-1}\dfrac{1}{3} + \tan^{-1}\dfrac{1}{7} =$ __________. (a) $\tan^{-1}\dfrac{4}{5}$ (b) $\dfrac{\pi}{2}$ (c) $1$ (d) $\dfrac{\pi}{4}$Preview
- Q81$\tan\left(\dfrac{\pi}{4} - 2\tan^{-1}\dfrac{1}{5}\right) =$ __________. (a) $\dfrac{7}{17}$ (b) $\dfrac{17}{7}$ (c) $-\dfrac{7}{17}$ (d) $-…Preview
- Q82The principal value branch of $\sec^{-1}x$ is __________. (a) $(0, \pi)$ (b) $[0, \pi]$ (c) $[0,\pi] - \left\{\dfrac{\pi}{2}\right\}$ (d) $\…Preview
- Q83$\cos\left(\tan^{-1}\dfrac{1}{3} + \tan^{-1}\dfrac{1}{2}\right) =$ ____________. (a) $\dfrac{1}{\sqrt{2}}$ (b) $\dfrac{\sqrt{3}}{2}$ (c) $\d…Preview
- Q84If $\tan\theta + \tan 2\theta + \tan 3\theta = \tan\theta\tan 2\theta\tan 3\theta$, then the general value of $\theta$ is _______. (a) $n\pi…Preview
- Q85In any $\triangle ABC$, if $a\cos B = b\cos A$, then the triangle is ________. (a) Equilateral triangle (b) Isosceles triangle (c) Scalene (…Preview
- Q86Find the principal solutions of the equation $\sin 2\theta = -\dfrac{1}{2}$Preview
- Q87Find the principal solutions of the equation $\tan 3\theta = -1$Preview
- Q88Find the principal solutions of the equation $\cot\theta = 0$Preview
- Q89Find the principal solutions of the equation $\sin 2\theta = -\dfrac{1}{2}$Preview
- Q90Find the principal solutions of the equation $\tan 5\theta = -1$Preview
- Q91Find the principal solutions of the equation $\cot 2\theta = 0$Preview
- Q92Which of the following equations have no solutions? (i) $\cos 2\theta = \dfrac{1}{3}$ (ii) $\cos^2\theta = -1$ (iii) $2\sin\theta = 3$ (iv)…Preview
- Q93Find the general solution of the equation $\tan\theta = -\sqrt{3}$Preview
- Q94Find the general solution of the equation $\tan^2\theta = 3$Preview
- Q95Find the general solution of the equation $\sin\theta - \cos\theta = 1$Preview
- Q96Find the general solution of the equation $\sin 2\theta - \cos 2\theta = 1$Preview
- Q97In $\triangle ABC$ prove that $\dfrac{\cos\dfrac{A-B}{2}}{\sin\dfrac{C}{2}} = \dfrac{a+b}{c}$.Preview
- Q98With usual notations prove that $(a-b)^2\cos^2\dfrac{C}{2} + (a+b)^2\sin^2\dfrac{C}{2} = c^2$.Preview
- Q99In $\triangle ABC$ prove that $(a+b)^2\cos^2\dfrac{C}{2} + (a-b)^2\sin^2\dfrac{C}{2} = a^2 + b^2 + 2ab\cos C$.Preview
- Q100In $\triangle ABC$ if $\cos A = \sin B - \cos C$ then show that it is a right angled triangle.Preview
- Q101[Source text badly corrupted at this item — the printed condition involving $\sin(A-B)$, $\sin(B-?)$ and side $c$ could not be reliably reco…Preview
- Q102Solve the triangle in which $a = \sqrt{3}+1$, $b = \sqrt{3}-1$ and $C = 60^\circ$.Preview
- Q103In $\triangle ABC$ prove that $a\sin A - b\sin B = c\sin(A-B)$.Preview
- Q104In $\triangle ABC$ prove that $\dfrac{c - b\cos A}{b - c\cos A} = \dfrac{\cos B}{\cos C}$.Preview
- Q105In $\triangle ABC$ prove that $a^2\sin(B-C) = (b^2-c^2)\sin A$.Preview
- Q106In $\triangle ABC$ prove that $ac\cos B - bc\cos A = a^2 - b^2$.Preview
- Q107In $\triangle ABC$ prove that $\dfrac{\cos A}{a} + \dfrac{\cos B}{b} + \dfrac{\cos C}{c} = \dfrac{a^2+b^2+c^2}{2abc}$.Preview
- Q108In $\triangle ABC$ prove that $\dfrac{1-\cos 2A}{a^2} = \dfrac{1-\cos 2B}{b^2}$.Preview
- Q109In $\triangle ABC$ prove that $\dfrac{\tan\dfrac{B-C}{2}}{\tan\dfrac{B+C}{2}} = \dfrac{b-c}{b+c}$.Preview
- Q110In $\triangle ABC$ if $a^2$, $b^2$, $c^2$ are in A.P. then show that $\cot A$, $\cot B$, $\cot C$ are also in A.P.Preview
- Q111In $\triangle ABC$ if $C = 90^\circ$ then prove that $\sin(A-B) = \dfrac{a^2-b^2}{a^2+b^2}$.Preview
- Q112In $\triangle ABC$ if $\dfrac{\cos A}{a} = \dfrac{\cos B}{b}$ then show that it is an isosceles triangle.Preview
- Q113In $\triangle ABC$ if $\sin^2 A + \sin^2 B = \sin^2 C$ then prove that the triangle is a right angled triangle.Preview
- Q114In $\triangle ABC$ prove that $a^2(\cos^2 B - \cos^2 C) + b^2(\cos^2 C - \cos^2 A) + c^2(\cos^2 A - \cos^2 B) = 0$.Preview
- Q115With usual notations show that $(c^2-a^2+b^2)\tan A = (a^2-b^2+c^2)\tan B = (b^2-c^2+a^2)\tan C$.Preview
- Q116In $\triangle ABC$ if $b\cos^2\dfrac{A}{2} + a\cos^2\dfrac{B}{2} = \dfrac{3c}{2}$ then prove that $a$, $b$, $c$ are in A.P.Preview
- Q117Show that $2\sin^{-1}\dfrac{3}{5} = \tan^{-1}\dfrac{24}{7}$.Preview
- Q118Show that $\tan^{-1}\dfrac{1}{5} + \tan^{-1}\dfrac{1}{7} + \tan^{-1}\dfrac{1}{3} + \tan^{-1}\dfrac{1}{8} = \dfrac{\pi}{4}$.Preview
- Q119Prove that $\tan^{-1}x = \dfrac{1}{2}\cos^{-1}\left(\dfrac{1-x^2}{1+x^2}\right)$, if $x \in [0,1]$.Preview
- Q120[Source text badly corrupted at this item — the numeric constants of this $\sin^{-1}$ identity could not be reliably reconstructed from the…Preview
- Q121Show that $\tan^{-1}\sqrt{\dfrac{1-x}{1+x}} = \dfrac{\pi}{4} - \dfrac{1}{2}\cos^{-1}x$, for $-1 \le x \le 1$.Preview
- Q122If $\sin\left(\sin^{-1}\dfrac{1}{5} + \cos^{-1}x\right) = 1$ then find the value of $x$.Preview
- Q123If $\tan^{-1}\dfrac{x-1}{x-2} + \tan^{-1}\dfrac{x+1}{x+2} = \dfrac{\pi}{4}$ then find the value of $x$.Preview
- Q124If $2\tan^{-1}(\cos x) = \tan^{-1}(\text{cosec}\,x)$ then find the value of $x$.Preview
- Q125Solve: $\tan^{-1}\dfrac{1-x}{1+x} = \dfrac{1}{2}\tan^{-1}x$, for $x > 0$.Preview
- Q126If $\sin^{-1}(1-x) - 2\sin^{-1}x = \dfrac{\pi}{2}$ then find the value of $x$.Preview
- Q127If $\tan^{-1}(2x) + \tan^{-1}(3x) = \dfrac{\pi}{2}$ then find the value of $x$.Preview
- Q128Show that $\tan^{-1}\dfrac{1}{2} + \tan^{-1}\dfrac{1}{5} + \tan^{-1}\dfrac{1}{8} = \dfrac{\pi}{4}$.Preview
- Q129Show that $\cot^{-1}\dfrac{1}{3} - \tan^{-1}\dfrac{1}{3} = \cot^{-1}\dfrac{3}{4}$.Preview
- Q130[Source text badly corrupted at this item — the numeric constants of this $\tan^{-1}$ identity could not be reliably reconstructed from the…Preview
- Q131[Source text badly corrupted at this item — the numeric constants of this inverse-trigonometric identity could not be reliably reconstructed…Preview
- Q132[Source text badly corrupted at this item — the numeric constants of this $\cot^{-1}$/$\sec^{-1}$ identity could not be reliably reconstruct…Preview
- Q133Prove that $\cos^{-1}x = 2\tan^{-1}\sqrt{\dfrac{1-x}{1+x}}$, for $-1 \le x \le 1$.Preview
- Q134[Source text badly corrupted at this item — the second sub-identity in this pair could not be reliably distinguished from the first during e…Preview
- Q135If $|x| < 1$, then prove that $2\tan^{-1}x = \tan^{-1}\dfrac{2x}{1-x^2} = \sin^{-1}\dfrac{2x}{1+x^2} = \cos^{-1}\dfrac{1-x^2}{1+x^2}$.Preview
- Q136If $x, y, z$ are positive then prove that $\tan^{-1}\dfrac{x-y}{1+xy} + \tan^{-1}\dfrac{y-z}{1+yz} + \tan^{-1}\dfrac{z-x}{1+zx} = 0$.Preview
- Q137If $\tan^{-1}x + \tan^{-1}y + \tan^{-1}z = \dfrac{\pi}{2}$ then show that $xy + yz + zx = 1$.Preview
- Q138If $\cos^{-1}x + \cos^{-1}y + \cos^{-1}z = \pi$ then show that $x^2 + y^2 + z^2 + 2xyz = 1$.Preview