Skip to content

Mathematics · Ch 3 — Trigonometric Functions

Inverse Trigonometric Functions

3.3

Inverse Trigonometric Functions

So far we have treated sin⁡\sin, cos⁡\cos, tan⁡\tan, etc. as functions that take an angle and produce a number. This section asks the reverse question: given the number, can we recover the angle? Recall that a function f:A→Bf:A\to B has an inverse f−1:B→Af^{-1}:B\to A only when ff is one-one and onto; for y=f(x)y=f(x), the inverse says x=f−1(y)x=f^{-1}(y), and domain(f−1)=range(f)\text{domain}(f^{-1})=\text{range}(f), range(f−1)=domain(f)\text{range}(f^{-1})=\text{domain}(f). But no trigonometric function is one-one on its full domain — e.g. sin⁡θ=k\sin\theta=k (for ∣k∣<1|k|<1) already has infinitely many solutions θ=nπ+(−1)nα\theta=n\pi+(-1)^n\alpha (Theorem 3.1), so infinitely many angles share one sine value, and sin⁡\sin cannot be inverted on all of R\mathbb{R}. However, examining the graph of each trigonometric function shows that on a suitably chosen restricted interval of its domain, it is one-one and onto — and it is only on that restricted int …

Table 1Domain, range and period of the trigonometric functions
FunctionDomainRangePeriod
sinR\mathbb{R}[−1,1][-1,1]2π2\pi
cosR\mathbb{R}[−1,1][-1,1]2π2\pi
tanR−{(2n+1)π2:n∈Z}\mathbb{R} - \left\{(2n+1)\dfrac{\pi}{2} : n\in\mathbb{Z}\right\}R\mathbb{R}π\pi
cotR−{nπ:n∈Z}\mathbb{R} - \{n\pi : n\in\mathbb{Z}\}R\mathbb{R}π\pi
secR−{(2n+1)π2:n∈Z}\mathbb{R} - \left\{(2n+1)\dfrac{\pi}{2} : n\in\mathbb{Z}\right\}R−(−1,1)\mathbb{R}-(-1,1)2π2\pi