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Miscellaneous Exercise 3 · Q66

Q.The principal solutions of equation sin⁡θ=−12\sin\theta = -\dfrac{1}{2} are ____________.

(a) π6,5π6\dfrac{\pi}{6}, \dfrac{5\pi}{6}
(b) 7π6,11π6\dfrac{7\pi}{6}, \dfrac{11\pi}{6}
(c) π6,7π6\dfrac{\pi}{6}, \dfrac{7\pi}{6}
(d) 5π6,11π6\dfrac{5\pi}{6}, \dfrac{11\pi}{6}
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✓ Free question

sin⁡θ=−12\sin\theta=-\dfrac12 is negative, so θ\theta lies in the third or fourth quadrant with reference angle π6\dfrac{\pi}{6}: θ=π+π6=7π6\theta=\pi+\dfrac{\pi}{6}=\dfrac{7\pi}{6} or θ=2π−π6=11π6\theta=2\pi-\dfrac{\pi}{6}=\dfrac{11\pi}{6}.

✓Final answer

(b) 7π6,11π6\dfrac{7\pi}{6},\dfrac{11\pi}{6}

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