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Exercises · 9.25

Q.Write chemical reactions to justify that hydrogen peroxide can function as an oxidising as well as reducing agent.

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Hydrogen peroxide has an intermediate oxidation state of oxygen (−1), so it can either be reduced further (to −2 in H2O, acting as an oxidising agent) or oxidised (to 0 in O2, acting as a reducing agent), depending on the other reactant.

As an oxidising agent — H2O2 oxidises lead(II) sulphide to lead(II) sulphate (used to restore blackened lead-based paintings, converting black PbS back to white PbSO4):

PbS(s)+4H2O2(aq)→PbSO4(s)+4H2O(l)PbS(s) + 4H_2O_2(aq) \rightarrow PbSO_4(s) + 4H_2O(l)

It can also oxidise Fe²⁺ to Fe³⁺:

2Fe2+(aq)+2H+(aq)+H2O2(aq)→2Fe3+(aq)+2H2O(l)2Fe^{2+}(aq) + 2H^+(aq) + H_2O_2(aq) \rightarrow 2Fe^{3+}(aq) + 2H_2O(l)

As a reducing agent — H2O2 reduces acidified potassium permanganate, itself being oxidised to O2 gas:

2MnO4−(aq)+6H+(aq)+5H2O2(aq)→2Mn2+(aq)+5O2(g)+8H2O(l)2MnO_4^-(aq) + 6H^+(aq) + 5H_2O_2(aq) \rightarrow 2Mn^{2+}(aq) + 5O_2(g) + 8H_2O(l) …

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