Q.Write the nuclear reaction of bombarded with a slow neutron. Calculate the energy released in KWh in the fission of 50 kg of . OR Using Bohr's quantization condition for angular momentum of an electron revolving around the hydrogen nucleus, establish the expression of the radius of the stationary orbits of hydrogen atom.
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Each U-235 fission releases ~200 MeV; multiplying by the number of atoms in 50 kg and converting to kWh gives about kWh. (OR alternative: Bohr's quantization gives .)
Part 1 (primary): Nuclear fission of U-235 and energy released
Nuclear reaction. When is bombarded with a slow ("thermal") neutron, it forms an unstable compound nucleus , which splits (fissions) into two lighter nuclei, releasing 2–3 fast neutrons and a large amount of energy. A representative fission reaction is:
(Many different fission fragment pairs are possible; this is one typical example. Charge and mass number both balance: ; .)
Energy per fission. Each fission event of releases, on average, about
Number of atoms in 50 kg of . Using Avogadro's number per mole and molar mass :
Total energy released:
Converting to kWh (using ):
Part 2 (OR): Bohr's radius of the hydrogen atom's stationary orbits
Bohr postulated that an electron can revolve only in those orbits where its angular momentum is quantised in integral multiples of :
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.