Q.(i) An atomic orbital has n = 3. What are the possible values of l and ?
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Start your 14-day free trial to unlock the full solution →The quantum numbers and are determined by the principal quantum number and the orbital shape. For , can be 0, 1, or 2, and ranges from to . The 3d orbital has and . Among 1p, 2s, 2p, and 3f, only 2s and 2p are possible.
The Core Idea: Why Quantum Numbers Are Not Arbitrary
In quantum mechanics, an electron in an atom is described by a set of four quantum numbers. The first three — , , and — come directly from solving the Schrödinger equation for the hydrogen atom. They are not random; they are linked by strict rules.
The principal quantum number (1, 2, 3, …) sets the energy level and roughly the size of the orbital. The azimuthal quantum number defines the shape of the orbital (s, p, d, f, …) and can only take integer values from 0 up to . The magnetic quantum number describes the orientation of the orbital in space, and it ranges from to in integer steps.
So the moment you know , you know the possible values. And once you know , you know the possible values. This is the chain of dependence.
(i) For , what are the possible values of and ?
Step 1: Determine possible values.
The rule: can be 0, 1, 2, …, up to .
For , . So can be:
These correspond to the 3s, 3p, and 3d orbitals respectively.
Step 2: For each , find possible values.
takes integer values from to , including zero.
- If : (only one orientation — the s orbital is spherical).
- If : (three orientations — the three p orbitals).
- If : (five orientations — the five d orbitals).
A common mistake is to think can be any integer between and including values like for . It cannot — the range is strictly to . For , the maximum is 2.
So the complete set for is:
| values | |
|---|---|
| 0 | 0 |
| 1 | -1, 0, +1 |
| 2 | -2, -1, 0, +1, +2 |
(ii) Quantum numbers ( and ) for the 3d orbital
The notation "3d" tells you two things directly:
- The number "3" is .
- The letter "d" means (since s=0, p=1, d=2, f=3).
So for a 3d orbital, is fixed at 2. The possible values are therefore:
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