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Exercises · 2.5

Q.Yellow light emitted from a sodium lamp has a wavelength (λ\lambda) of 580 nm. Calculate the frequency (ν\nu) and wavenumber (νˉ\bar{\nu}) of the yellow light.

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Yellow light is an electromagnetic wave; its frequency and wavenumber follow directly from the fundamental wave relation c=νλc = \nu \lambda and the definition νˉ=1/λ\bar{\nu} = 1/\lambda. For sodium's 580 nm emission: ν=5.17×1014 Hz\nu = 5.17 \times 10^{14} \, \text{Hz} and νˉ=1.72×106 m−1\bar{\nu} = 1.72 \times 10^{6} \, \text{m}^{-1}.

Why these quantities matter

Electromagnetic radiation can be described in three equivalent ways: wavelength λ\lambda (the spatial extent of one cycle), frequency ν\nu (how many cycles pass a point per second), and wavenumber νˉ\bar{\nu} (how many wavelengths fit in a unit distance). All three are connected through the speed of light cc, which is constant in vacuum at 3.00×108 m/s3.00 \times 10^8 \, \text{m/s}.

The wavelength tells us the color we perceive. The frequency tells us the energy per photon (through E=hνE = h\nu). The wavenumber is particularly useful in spectroscopy because it's directly proportional to energy and conveniently expressed in cm−1\text{cm}^{-1} for infrared and Raman work.

Step-by-step calculation

1. Convert wavelength to SI units

The given wavelength is λ=580 nm\lambda = 580 \, \text{nm}. Since all our constants are in SI, we need meters:

λ=580 nm=580×10−9 m=5.80×10−7 m\lambda = 580 \, \text{nm} = 580 \times 10^{-9} \, \text{m} = 5.80 \times 10^{-7} \, \text{m}

2. Calculate frequency using the wave equation

The fundamental relationship for any wave is:

c=νλc = \nu \lambda

Rearranging for frequency:

ν=cλ=3.00×108 m/s5.80×10−7 m\nu = \frac{c}{\lambda} = \frac{3.00 \times 10^8 \, \text{m/s}}{5.80 \times 10^{-7} \, \text{m}}

ν=5.17×1014 s−1=5.17×1014 Hz\nu = 5.17 \times 10^{14} \, \text{s}^{-1} = 5.17 \times 10^{14} \, \text{Hz}

This enormous number makes sense: visible light oscillates hundreds of trillions of times per second.

3. Calculate wavenumber

Wavenumber is simply the reciprocal of wavelength:

νˉ=1λ=15.80×10−7 m\bar{\nu} = \frac{1}{\lambda} = \frac{1}{5.80 \times 10^{-7} \, \text{m}}

νˉ=1.72×106 m−1\bar{\nu} = 1.72 \times 10^{6} \, \text{m}^{-1} …

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