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Exercises · 2.3

Q.How many neutrons and protons are there in the following nuclei? 613C, 816O, 1224Mg, 2656Fe, 3888Sr^{13}_{6}C,\ ^{16}_{8}O,\ ^{24}_{12}Mg,\ ^{56}_{26}Fe,\ ^{88}_{38}Sr

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For any nucleus written as ZAX^{A}_{Z}X, the atomic number ZZ gives the number of protons, and the neutron count is A−ZA - Z. Applying this to the given nuclei: 613C^{13}_{6}C has 6 protons and 7 neutrons; 816O^{16}_{8}O has 8 protons and 8 neutrons; 1224Mg^{24}_{12}Mg has 12 protons and 12 neutrons; 2656Fe^{56}_{26}Fe has 26 protons and 30 neutrons; 3888Sr^{88}_{38}Sr has 38 protons and 50 neutrons.

The idea: reading a nuclear symbol

Every nucleus is written in the standard notation ZAX^{A}_{Z}X, where:

  • XX is the chemical symbol of the element.
  • ZZ is the atomic number — the number of protons. This defines which element it is.
  • AA is the mass number — the total number of protons plus neutrons.

The number of neutrons NN is simply the difference: N=A−ZN = A - Z.

That’s the entire principle. There is no hidden complexity — it’s just careful subtraction once you’ve correctly identified ZZ and AA from the superscript and subscript.

Watch out

A common mistake is to confuse the mass number AA with the atomic mass (which is not an integer). Here, AA is always a whole number — it counts nucleons, not grams. Also, never assume the number of neutrons equals the number of protons; that’s only true for a few light stable nuclei.

Step-by-step for each nucleus

1. 613C^{13}_{6}C

The subscript is Z=6Z = 6, so there are 6 protons.

The superscript is A=13A = 13, so neutrons = 13−6=713 - 6 = 7.

2. 816O^{16}_{8}O

Z=8Z = 8 → 8 protons.

A=16A = 16 → neutrons = 16−8=816 - 8 = 8.

3. 1224Mg^{24}_{12}Mg

Z=12Z = 12 → 12 protons.

A=24A = 24 → neutrons = 24−12=1224 - 12 = 12.

4. 2656Fe^{56}_{26}Fe

Z=26Z = 26 → 26 protons.

A=56A = 56 → neutrons = 56−26=3056 - 26 = 30.

5. 3888Sr^{88}_{38}Sr

Z=38Z = 38 → 38 protons.

A=88A = 88 → neutrons = 88−38=5088 - 38 = 50.

Tip

Notice that for 816O^{16}_{8}O and 1224Mg^{24}_{12}Mg, the number of protons equals the number of neutrons. This is a special case — these are “doubly magic” or light stable nuclei where N=ZN = Z. For heavier elements like iron and strontium, neutrons outnumber protons, which is the general trend for stability.

✓Final answer

The proton and neutron counts are: 613C^{13}_{6}C: 6 protons, 7 neutrons; 816O^{16}_{8}O: 8 protons, 8 neutrons; 1224Mg^{24}_{12}Mg: 12 protons, 12 neutrons; 2656Fe^{56}_{26}Fe: 26 protons, 30 neutrons; 3888Sr^{88}_{38}Sr: 38 protons, 50 neutrons.

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