Evaluation · Q4
Q.For every CO2 molecule entering the C3 cycle, the number of ATP & NADPH required
a. 2ATP + 2NADPH
b. 2ATP + 3NADPH
c. 3ATP + 2NADPH
d. 3ATP + 3NADPH
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Start your 14-day free trial to unlock the full solution →Step 1. The Calvin cycle's overall stoichiometry, scaled to make one hexose sugar, is fixing 6 CO2 using 18 ATP and 12 NADPH+H+.
Step 2. Dividing this overall cost by the 6 CO2 molecules fixed gives the per-CO2 cost: 18 ATP / 6 = 3 ATP, and 12 NADPH+H+ / 6 = 2 NADPH+H+.
Step 3. This matches the cycle's own internal bookkeeping: for each PGA-to-G3P conversion (from each CO2 fixed) the reduction phase spends 1 ATP (phosphorylating PGA) and 1 NADPH+H+ (reducing it to G3P), and the regeneration phase spends a further roughly 2 ATP overall per CO2 fixed regenerating RuBP - toget …
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