Q.In Botany class, teacher explains, Synthesis of one glucose requires 30 ATPs in C4 plants and only 18 ATPs in C3plants. The same teacher explains C4 plants are more advantageous than C3 plants. Can you identify the reason for this contradiction?
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1. The raw ATP figures are correct as the teacher states them: C3 plants spend 18 ATP to synthesise one glucose molecule, while C4 plants spend more, 30 ATP, because of the extra ATP the C4 pathway spends re-phosphorylating pyruvate back into PEP in the mesophyll cell at every turn of the cycle.
Step 2. Taken purely as a direct-cost comparison, this does make C4 photosynthesis look less "efficient" in ATP terms - but ATP cost of fixation alone is not the same thing as overall photosynthetic productivity.
Step 3. C3 plants suffer a separate, substantial loss that the 18-ATP figure does not capture at all: whenever CO2 is scarce and O2 relatively abundant (common under bright, hot conditions), RuBisCO in C3 plants switches to its oxygenase role and drives photorespiration, which yields no ATP and can waste up to 50% of the plant's overall photosynthetic potential.
Step 4. C4 plants, by concentrating CO2 around RuBisCO in their bundle sheath cells (section 13.14), suppress this photorespiratory loss almost entirely - so while they pay a higher direct ATP price for fixation itself, they avoid the much larger indirect loss that C3 plants incur through photorespiration. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.