Skip to content
Choose the Best Answer · Q16

Q.If n = 6, the correct sequence for filling of electrons will be

(a) ns→(n−2)f→(n−1)d→npns\rightarrow(n-2)f\rightarrow(n-1)d\rightarrow np
(b) ns→(n−1)d→(n−2)f→npns\rightarrow(n-1)d\rightarrow(n-2)f\rightarrow np
(c) ns→(n−2)f→np→(n−1)dns\rightarrow(n-2)f\rightarrow np\rightarrow(n-1)d
(d) none of these are correct
Puducherry TnboardTextbookSubjectiveImportance★★★★★est
22% · 16/73 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. For n=6n=6: ns=6sns=6s has (n+l)=6(n+l)=6; (n−2)f=4f(n-2)f=4f has (n+l)=4+3=7(n+l)=4+3=7; (n−1)d=5d(n-1)d=5d has (n+l)=5+2=7(n+l)=5+2=7; np=6pnp=6p has (n+l)=6+1=7(n+l)=6+1=7.

Step 2. By increasing (n+l)(n+l): 6s6s (6) fills first. Then among 4f, 5d, 6p, all share (n+l)=7(n+l)=7, so the tie-break is smaller nn: 4f4f (n=4n=4) before 5d5d (n=5n=5) before 6p6p (n=6n=6). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.