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Write Brief Answer · Q51

Q.Identify the missing quantum numbers and the sub energy level: (row 1) n=?, l=?, m=0n=?,\ l=?,\ m=0, sub energy level =4d=4d; (row 2) n=3, l=1, m=0n=3,\ l=1,\ m=0, sub energy level =?=?; (row 3) n=?, l=?, m=?n=?,\ l=?,\ m=?, sub energy level =5p=5p; (row 4) n=?, l=?, m=−2n=?,\ l=?,\ m=-2, sub energy level =3d=3d.

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Step 1. Row 1: sub energy level given as 4d, so n=4, l=2n=4,\ l=2 (d ⇒ l=2). Given m=0m=0, which is a valid value within −2-2 to +2+2 - consistent.

Step 2. Row 2: given n=3, l=1, m=0n=3,\ l=1,\ m=0. The subshell letter for l=1l=1 is p, and n=3n=3 gives the sub energy level 3p.

Step 3. Row 3: sub energy level given as 5p, so n=5, l=1n=5,\ l=1 (p ⇒ l=1). The subshell letter alone does not uniquely fix mm - any of −1,0,-1, 0, or +1+1 is consistent with "5p" - so mm can be any one of −1,0,+1-1,0,+1 (not uniquely determined from the information given). …

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