Skip to content
Question 121 of 143

Q.If f(x)=xtan⁡−1xf(x) = x\tan^{-1}x then, f′(0)+f′(1)f'(0) + f'(1) is:

(a) 1+π41 + \dfrac{\pi}{4}
(b) 12+π4\dfrac{1}{2} + \dfrac{\pi}{4}
(c) 12−π4\dfrac{1}{2} - \dfrac{\pi}{4}
(d) 2
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2020MCQ· 1mImportance★★★★★
85% · 121/143 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Differentiate using the product rule, then substitute x=0x=0 and x=1x=1 and add.

f(x)=xtan⁡−1xf(x)=x\tan^{-1}x. By the product rule, f′(x)=(x)′tan⁡−1x+x(tan⁡−1x)′=tan⁡−1x+x1+x2f'(x)=(x)'\tan^{-1}x+x(\tan^{-1}x)'=\tan^{-1}x+\dfrac{x}{1+x^2}.

At x=0x=0: f′(0)=tan⁡−10+01=0+0=0f'(0)=\tan^{-1}0+\dfrac{0}{1}=0+0=0.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.