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Question 131 of 143

Q.If y=f(x2+2)y=f(x^2+2) and f′(3)=5f'(3)=5, then dydx\dfrac{dy}{dx} at x=1x=1 is:

(a) 1515
(b) 55
(c) 1010
(d) 2525
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2024MCQ· 1mImportance★★★★★
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By the chain rule, dydx∣x=1=10\dfrac{dy}{dx}\Big|_{x=1}=10.

y=f(x2+2)y=f(x^2+2), so by the chain rule:

dydx=f′(x2+2)⋅2x.\dfrac{dy}{dx}=f'(x^2+2)\cdot 2x.

At x=1x=1: x2+2=3x^2+2=3, so f′(x2+2)=f′(3)=5f'(x^2+2)=f'(3)=5 (given). Thus …

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