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Question 124 of 143

Q.If y=f(x2+2)y=f(x^2+2) and f′(3)=5f'(3)=5 then, dydx\dfrac{dy}{dx} at x=1x=1 is:

(a) 15
(b) 5
(c) 10
(d) 25
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2022MCQ· 1mImportance★★★★★
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Using the chain rule, dydx∣x=1=f′(3)⋅2(1)=10\dfrac{dy}{dx}\Big|_{x=1} = f'(3)\cdot 2(1) = 10.

Given y=f(x2+2)y = f(x^2+2), by the chain rule dydx=f′(x2+2)⋅ddx(x2+2)=f′(x2+2)⋅2x\dfrac{dy}{dx} = f'(x^2+2)\cdot \dfrac{d}{dx}(x^2+2) = f'(x^2+2)\cdot 2x.

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