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Question 130 of 143

Q.Differentiate with respect to xx. y=cos⁡xx3y = \dfrac{\cos x}{x^3}

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2023Subjective· 3mImportance★★★★★
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The quotient rule (uv)′=u′v−uv′v2\left(\dfrac{u}{v}\right)' = \dfrac{u'v-uv'}{v^2} with u=cos⁡xu=\cos x, v=x3v=x^3 gives the derivative after factoring out x2x^2.

Let u=cos⁡xu=\cos x, v=x3v=x^3. Then u′=−sin⁡xu'=-\sin x, v′=3x2v'=3x^2.

By the quotient rule:

dydx=u′v−uv′v2=(−sin⁡x)(x3)−(cos⁡x)(3x2)x6\frac{dy}{dx} = \frac{u'v-uv'}{v^2} = \frac{(-\sin x)(x^3)-(\cos x)(3x^2)}{x^6}

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