Skip to content
Exercise 3.2 · Q10

Q.A train is moving on a circular track of 15001500 m radius at the rate of 6666 km/hr. What angle will it turn in 2020 seconds?

Puducherry TnboardTextbookSubjectiveImportance★★★★★
13% · 22/175 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Convert the train's speed to metres per second, use it to find the arc length covered in 2020 seconds, apply θ=s/r\theta=s/r to get the angle in radians, then convert to degrees — using π≈227\pi\approx\tfrac{22}{7} gives an exact, clean answer here.

Step 1. Convert speed to m/s. 66 km/hr=66×10003600 m/s=660003600=553 m/s66\ \text{km/hr} = \dfrac{66\times1000}{3600}\ \text{m/s} = \dfrac{66000}{3600}=\dfrac{55}{3}\ \text{m/s}.

Step 2. Find the distance covered in 2020 seconds.

s=553×20=11003 m.s=\frac{55}{3}\times20=\frac{1100}{3}\ \text{m}.

Step 3. Find the angle turned, θ=s/r\theta=s/r.

θ=1100/31500=11004500=1145 radians.\theta=\frac{1100/3}{1500}=\frac{1100}{4500}=\frac{11}{45}\ \text{radians}. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.