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Exercise 3.2 · Q8

Q.The perimeter of a certain sector of a circle is equal to the length of the arc of a semi-circle having the same radius. Express the angle of the sector in degrees, minutes and seconds.

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Write both the sector's perimeter and the semicircle's arc length in terms of the same radius rr, equate them (the rr cancels), solve for θ\theta in radians, then convert to degrees-minutes-seconds using π≈227\pi\approx\tfrac{22}{7}.

Step 1. Express the sector's perimeter. A sector of radius rr and central angle θ\theta (radians) has perimeter = two straight radii plus the arc: 2r+rθ2r+r\theta.

Step 2. Express the semicircle's arc length (same radius rr). A semicircle is a sector with central angle π\pi radians, so its arc length is rπr\pi.

Step 3. Equate the two (same radius, so it cancels).

2r+rθ=πr ⇒ 2+θ=π ⇒ θ=π−2 radians.2r+r\theta=\pi r \ \Rightarrow\ 2+\theta=\pi \ \Rightarrow\ \theta=\pi-2 \ \text{radians}.

Step 4. Convert to degrees using π≈227\pi\approx\dfrac{22}{7}. θ=227−2=22−147=87\theta=\dfrac{22}{7}-2=\dfrac{22-14}{7}=\dfrac{8}{7} radians. …

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