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Exercise 3.2 · Q6

Q.What is the length of the arc intercepted by a central angle of measure 41∘41^\circ in a circle of radius 1010 ft?

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Since s=rθs=r\theta needs θ\theta in radians, first convert the given 41∘41^\circ using θ=πx180\theta=\dfrac{\pi x}{180}, then multiply by the radius.

Step 1. Convert 41∘41^\circ to radians. θ=41π180\theta=\dfrac{41\pi}{180} radians.

Step 2. Apply s=rθs=r\theta.

s=10×41π180=410π180=41π18 ft.s=10\times\frac{41\pi}{180}=\frac{410\pi}{180}=\frac{41\pi}{18}\ \text{ft}. …

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