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Exercise 3.2 · Q4

Q.In a circle of diameter 4040 cm, a chord is of length 2020 cm. Find the length of the minor arc of the chord.

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The radius here happens to equal the chord length, which forces the triangle formed by the two radii and the chord to be equilateral, immediately giving a 60∘60^\circ central angle; converting to radians and applying s=rθs=r\theta finishes the problem.

Step 1. Find the radius. Diameter =40=40 cm, so radius r=20r=20 cm.

Step 2. Identify the triangle formed by the chord. The chord (length 2020 cm) together with the two radii to its endpoints (each also 2020 cm) forms a triangle with all three sides equal to 2020 cm — an equilateral triangle.

Step 3. Read off the central angle. All angles of an equilateral triangle are 60∘60^\circ, so the central angle subtended by this chord is θ=60∘=π3\theta=60^\circ=\dfrac{\pi}{3} radians. …

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