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I. Multiple Choice Questions · Q2

Q.A couple produces,

(a) pure rotation
(b) pure translation
(c) rotation and translation
(d) no motion
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✓ Free question

Step 1. Recall what defines a couple.

A couple consists of two forces F⃗\vec F and −F⃗-\vec F — equal in magnitude, opposite in direction — whose lines of action are separated by a nonzero perpendicular distance dd (they do not act along the same line).

Step 2. Compute the net force.

F⃗net=F⃗+(−F⃗)=0.\vec F_{net} = \vec F + (-\vec F) = 0.

Since Newton's second law for the center of mass gives F⃗net=Ma⃗CM\vec F_{net} = M\vec a_{CM}, a zero net force means a⃗CM=0\vec a_{CM}=0: the center of mass does not accelerate, so there is no translational motion produced by a couple.

Step 3. Compute the net torque.

Even though the forces cancel, they act along different lines, separated by dd. Taking torques about any point, the two torques add rather than cancel (because both forces try to turn the body the same rotational way about the gap between them), giving a nonzero net torque

τnet=Fd≠0.\tau_{net} = Fd \neq 0.

This nonzero torque produces angular acceleration, α=τnet/I≠0\alpha = \tau_{net}/I \neq 0.

Step 4. Combine the two results.

Zero net force + nonzero net torque = no translation, but definite rotation. That is exactly pure rotation, with the body spinning about its own center of mass while that center of mass stays put (e.g., turning a steering wheel or a screwdriver knob with two fingers).

Step 5. Rule out the other options.

  • (b) pure translation is wrong — that would need a nonzero net force with zero net torque, the opposite of a couple.
  • (c) rotation and translation is wrong — translation requires a⃗CM≠0\vec a_{CM}\neq 0, which needs nonzero net force; a couple's net force is always zero.
  • (d) no motion is wrong — the net torque is nonzero, so the body definitely does start rotating (unless already prevented by an external constraint, which isn't implied here).
✓Final answer

(a) pure rotation

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