Q.A flywheel rotates with a uniform angular acceleration. If its angular velocity increases from 20πrad s−1 to 40πrad s−1 in 10 seconds, find the number of rotations it makes in that period.
Imagine you're watching a ceiling fan. You know it's moving, but how do you describe how fast it's spinning? You could say "it makes 3 full turns every second" — that's a measure of angular velocity. But let's build this idea from the ground up.
The Intuition: Speed vs. Turning Speed
When a car moves in a straight line, we talk about its linear velocity — how many meters it covers per second. But when something rotates — a wheel, a planet, a spinning top — every point on it moves in a circle. The outer edge of a wheel travels a much longer distance in one rotation than a point near the centre. So if we tried to use ordinary speed (metres per second), we'd get different numbers for different parts of the same object. That's messy.
What we need is a quantity that describes the rotation itself, independent of how far a point is from the centre. That quantity is angular velocity.
The Core Idea
Angular velocity tells you how fast the angle is changing as something rotates. Instead of "metres per second," it's "radians per second" (or degrees per second, or revolutions per second).
Note
A radian is the natural unit for angles in physics. One full circle = 2π radians ≈ 6.28 rad. So "1 radian per second" means the object sweeps out an angle of about 57.3° every second.
The Precise Definition
Let an object rotate about a fixed axis. At time t, let its angular position be θ(t) — the angle it has turned through from some reference line. Then:
ω=dtdθ
where ω (Greek letter omega) is the instantaneous angular velocity. For uniform rotation (constant speed), this simplifies to:
ω=ΔtΔθ
Units: radians per second (rad/s). In practice, you'll also see revolutions per minute (rpm) — 1 rpm = 602π rad/s.
Direction Matters: Angular Velocity as a Vector
Here's where it gets interesting. Angular velocity isn't just a number — it has a direction. But the direction isn't "clockwise" or "anticlockwise" in the plane of rotation. Instead, it points along the axis of rotation, following the right-hand rule:
Tip
Curl the fingers of your right hand in the direction of rotation. Your thumb points in the direction of the angular velocity vector ω.
So a spinning wheel's angular velocity vector points straight out from its axle. If the wheel spins faster, the vector gets longer. If it reverses direction, the vector flips.
Connecting to Linear Velocity
Here's the payoff: once you know the angular velocity of a rotating object, you can find the linear speed of any point on it. For a point at distance r from the axis:
v=ωr
This is why the outer edge of a merry-go-round moves faster than a point near the centre — same ω, different r.
Watch out
This formula v=ωr only works when v is the tangential speed (perpendicular to the radius). It does NOT apply to radial motion (straight in or out).
A Concrete Example
A bicycle wheel spins at 120 rpm. What is its angular velocity in rad/s?
If the wheel has radius 0.35 m, a point on the rim moves at:
v=ωr=(12.57)(0.35)≈4.4 m/s
Why This Matters
Angular velocity is the foundation for understanding rotational motion — just as linear velocity is for straight-line motion. It leads directly to angular acceleration (α=dω/dt), rotational kinetic energy, torque, and angular momentum. Every time you see a spinning object, you're looking at angular velocity in action.
Angular velocity ω is the rate of change of angular position, measured in rad/s, with direction along the axis of rotation given by the right-hand rule.
Students preparing for boards often pair a search for "Angular Velocity class 11 physics" with "NCERT Physics syllabus" — Angular Velocity sits squarely within the Motion in a Plane / System of Particles and Rotational Motion coverage of NCERT Class 11 Physics, so it is fair game for both CBSE board questions and competitive-exam numericals. Working through the worked examples above alongside the official NCERT Physics textbook is the most reliable way to turn this understanding into exam-ready recall.
Use the rotational kinematics equations (the exact angular counterparts of the linear ones) to find the angular displacement, then convert to rotations.
✓Final answer
150 rotations.
Step 1. List the given data. Initial angular velocity ω1=20πrad s−1, final angular velocity ω2=40πrad s−1, time t=10s, and the angular acceleration is uniform (constant).
Step 2. Find the angular acceleration. Using the rotational counterpart of v=u+at:
Step 4. Convert angular displacement to number of rotations. One full rotation corresponds to an angular displacement of 2π rad, so:
N=2πθ=2π300π=150.
✓Final answer
The flywheel makes 150 complete rotations in the 10 seconds.
Rotational kinematics (angular counterpart of v=u+at and s=ut+1/2at^2)
Forgetting to convert the total angle theta (in radians) into number of rotations by dividing by 2*pi.
Using the average-angular-velocity shortcut (theta = (omega1+omega2)/2 * t) but making an arithmetic slip — this gives the same 300pi rad and is a valid cross-check, but must still be divided by 2pi at the end.
Mixing up omega1 and omega2 when computing alpha, giving a negative or wrong-magnitude angular acceleration.