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V. Numerical Problems · Q3

Q.A flywheel rotates with a uniform angular acceleration. If its angular velocity increases from 20π rad s−120\pi\ \text{rad s}^{-1} to 40π rad s−140\pi\ \text{rad s}^{-1} in 10 seconds, find the number of rotations it makes in that period.

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Step 1. List the given data. Initial angular velocity ω1=20π rad s−1\omega_1=20\pi\ \text{rad s}^{-1}, final angular velocity ω2=40π rad s−1\omega_2=40\pi\ \text{rad s}^{-1}, time t=10 st=10\ \text{s}, and the angular acceleration is uniform (constant).

Step 2. Find the angular acceleration. Using the rotational counterpart of v=u+atv=u+at:

ω2=ω1+αt⇒α=ω2−ω1t=40π−20π10=20π10=2π rad s−2.\omega_2=\omega_1+\alpha t\quad\Rightarrow\quad \alpha=\frac{\omega_2-\omega_1}{t}=\frac{40\pi-20\pi}{10}=\frac{20\pi}{10}=2\pi\ \text{rad s}^{-2}.

Step 3. Find the total angular displacement over the 10 s. Using the rotational counterpart of s=ut+12at2s=ut+\tfrac12at^2:

θ=ω1t+12αt2=(20π)(10)+12(2π)(10)2=200π+100π=300π rad.\theta=\omega_1t+\frac12\alpha t^2=(20\pi)(10)+\frac12(2\pi)(10)^2=200\pi+100\pi=300\pi\ \text{rad}.

Step 4. Convert angular displacement to number of rotations. One full rotation corresponds to an angular displacement of 2π2\pi rad, so:

N=θ2π=300π2π=150.N=\frac{\theta}{2\pi}=\frac{300\pi}{2\pi}=150.

✓Final answer

The flywheel makes 150150 complete rotations in the 10 seconds.

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