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Question 42 of 61

Q.(a)

(i) What are the applications of dimensional analysis?
(ii) Express 76 cm of mercury pressure in terms of Nm^-2 using the method of dimensions. OR
(b)
(i) Obtain a relation between momentum and kinetic energy.
(ii) Two objects of masses 2 kg and 4 kg are moving with the same momentum of 20 kgms^-1. (A) Will they have same kinetic energy? (B) Will they have same speed?
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2020Subjective· 5mImportance★★★★★
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Dimensional analysis checks equations, derives relations, and converts units; using P = hρg with h = 0.76 m, ρ(Hg) = 13600 kg/m^3, g = 9.8 m/s^2 gives 76 cm of mercury ≈ 1.01 × 10^5 N/m^2.

(i) Applications of dimensional analysis:

  1. To check the correctness (dimensional homogeneity) of a physical equation: the dimensions on the left-hand side of an equation must equal the dimensions on the right-hand side, for every term. If they don't match, the equation must be wrong.

  2. To derive a relationship between physical quantities: if it is known which quantities a given quantity depends on, dimensional analysis can be used to find the form of the relation between them (up to an unknown dimensionless constant).

  3. To convert a physical quantity's numerical value from one system of units to another (e.g. from CGS to SI), using the fact that the product (numerical value) × (unit) stays the same regardless of the unit system used.

(ii) Express 76 cm of mercury pressure in N/m^2:

The pressure exerted by a column of liquid of height h and density ρ is:

P = hρg

…

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