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Question 59 of 61

Q.If the error in the measurement of radius is 2%, then the error in the determination of volume of a sphere will be:

(a) 4%
(b) 8%
(c) 6%
(d) 2%
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2026MCQ· 1mImportance★★★★★
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Since V is proportional to r^3, the percentage error in volume is 3 times the percentage error in radius: 3 x 2% = 6%.

The volume of a sphere is

V = (4/3)pir^3

Taking logarithms (to apply the standard error-propagation rule for a power-law relationship):

ln V = ln(4*pi/3) + 3 ln r

Differentiating (treating errors as small quantities):

deltaV/V = 3 (deltar/r)

…

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