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Question 19 of 44

Q.Find the rank of the matrix A=(123234357)A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 3 & 4 \\ 3 & 5 & 7 \end{pmatrix}.

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2022Subjective· 2mImportance★★★★★
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ρ(A)=2\rho(A) = 2.

A=(123234357).A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 3 & 4 \\ 3 & 5 & 7 \end{pmatrix}.

Step 1 — test the full 3×33\times3 minor. Expand the determinant along the first row:

det⁡A=1(3⋅7−4⋅5)−2(2⋅7−4⋅3)+3(2⋅5−3⋅3).\det A = 1(3\cdot7 - 4\cdot5) - 2(2\cdot7 - 4\cdot3) + 3(2\cdot5 - 3\cdot3).

=1(21−20)−2(14−12)+3(10−9)=1−4+3=0.= 1(21 - 20) - 2(14 - 12) + 3(10 - 9) = 1 - 4 + 3 = 0.

Since det⁡A=0\det A = 0, the rank is less than 33.

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