Skip to content
Question 25 of 44

Q.Find the rank of the matrix [0−1524−6115]\begin{bmatrix} 0 & -1 & 5 \\ 2 & 4 & -6 \\ 1 & 1 & 5 \end{bmatrix}

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2023Subjective· 2mImportance★★★★★
57% · 25/44 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Evaluate the 3×33\times3 determinant; it equals 6eq06 eq0, so the rank is the full order, 33.

Let

A=[0−1524−6115].A=\begin{bmatrix}0&-1&5\\2&4&-6\\1&1&5\end{bmatrix}.

Expand ∣A∣|A| along the first row:

∣A∣=0∣4−615∣−(−1)∣2−615∣+5∣2411∣.|A|=0\begin{vmatrix}4&-6\\1&5\end{vmatrix}-(-1)\begin{vmatrix}2&-6\\1&5\end{vmatrix}+5\begin{vmatrix}2&4\\1&1\end{vmatrix}.

Compute the minors:

∣2−615∣=(2)(5)−(−6)(1)=10+6=16,\begin{vmatrix}2&-6\\1&5\end{vmatrix}=(2)(5)-(-6)(1)=10+6=16, …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.