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Question 39 of 44

Q.If the rank of the matrix (λ−100λ−1−10λ)\begin{pmatrix} \lambda & -1 & 0 \\ 0 & \lambda & -1 \\ -1 & 0 & \lambda \end{pmatrix} is 2 then λ\lambda is :

(a) 33
(b) 11
(c) Only real number
(d) 22
Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2026MCQ· 1mImportance★★★★★
89% · 39/44 Questions
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For a 3×33\times3 matrix, rank =2=2 means the determinant is 00 but at least one 2×22\times2 minor is non-zero. Setting det⁡=0\det=0 gives λ=1\lambda=1.

In the Tamil Nadu HSC Business Maths syllabus, the rank of a square matrix is 33 only when its determinant is non-zero; if the rank drops to 22, the determinant must be 00.

Expand along the first row of A=(λ−100λ−1−10λ)A=\begin{pmatrix} \lambda & -1 & 0 \\ 0 & \lambda & -1 \\ -1 & 0 & \lambda \end{pmatrix}:

det⁡A=λ∣λ−10λ∣−(−1)∣0−1−1λ∣+0\det A = \lambda\begin{vmatrix}\lambda & -1\\ 0 & \lambda\end{vmatrix} -(-1)\begin{vmatrix}0 & -1\\ -1 & \lambda\end{vmatrix} + 0

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