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Question 25 of 43

Q.Solve : 9y′′−12y′+4y=09y''-12y'+4y=0

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2023Subjective· 3mImportance★★★★★
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Equal roots m=23m=\tfrac23 give y=(A+Bx)e2x/3y=(A+Bx)e^{2x/3}.

9y′′−12y′+4y=0.9y''-12y'+4y=0.

Step 1 — auxiliary (characteristic) equation. Replace y′′→m2, y′→m, y→1y''\to m^2,\ y'\to m,\ y\to1:

9m2−12m+4=0.9m^{2}-12m+4=0.

Step 2 — solve it.

9m2−12m+4=(3m−2)2=0 ⇒ m=23, 23 (repeated root).9m^{2}-12m+4=(3m-2)^{2}=0\ \Rightarrow\ m=\frac23,\ \frac23\ (\text{repeated root}).

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