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Q.Find the differential equation of the curve x2+y2=a2x^2 + y^2 = a^2

Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2026Subjective· 2mImportance★★★★★
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x2+y2=a2x^2+y^2=a^2 contains one arbitrary constant, so one differentiation eliminates it: x+ydydx=0x+y\dfrac{dy}{dx}=0.

The family of curves x2+y2=a2x^2 + y^2 = a^2 (concentric circles centred at the origin) has a single arbitrary constant aa. To form the differential equation, differentiate with respect to xx:

ddx(x2)+ddx(y2)=ddx(a2)\frac{d}{dx}(x^2) + \frac{d}{dx}(y^2) = \frac{d}{dx}(a^2)

2x+2ydydx=0.2x + 2y\frac{dy}{dx} = 0.

Dividing throughout by 22:

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